(7x-12)^2=(2x)(19x-2)

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Solution for (7x-12)^2=(2x)(19x-2) equation: 



(7x-12)^2=(2x)(19x-2)

We move all terms to the left:

(7x-12)^2-((2x)(19x-2))=0



We calculate terms in parentheses: -(2x(19x-2)), so:

2x(19x-2)

We multiply parentheses

38x^2-4x

Back to the equation:

-(38x^2-4x)



We get rid of parentheses

-38x^2+(7x-12)^2+4x=0

We add all the numbers together, and all the variables

-38x^2+4x+(7x-12)^2=0

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